Question 1196858

 



given:
Longer base {{{a=16cm}}}
Shorter base {{{b=10cm}}}
height {{{h=4cm}}}


Perimeter=base1+base2+(2s), where {{{s}}}= the length of one of the non-parallel sides of the isosceles trapezoid. 


first find {{{s}}}

{{{s=sqrt(4^2+((16-10)/2)^2)=sqrt(16+9)=sqrt(25)=5cm}}}


Perimeter is {{{P=16cm+cm+2*5cm=36cm}}}


and area is:

 {{{A = (( 16cm+ 10cm) * 4cm) / 2}}}

{{{A = 26cm* 2cm}}}

{{{A=52cm^2}}}