Question 1196819
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n = 52 cards
r = 8 selections
The order doesn't matter


Use the nCr combination formula


n C r = (n!)/(r!(n-r)!)
52 C 8 = (52!)/(8!*(52-8)!)
52 C 8 = (52!)/(8!*44!)
52 C 8 = (52*51*50*49*48*47*46*45*44!)/(8!*44!)
52 C 8 = (52*51*50*49*48*47*46*45)/(8!)
52 C 8 = (52*51*50*49*48*47*46*45)/(8*7*6*5*4*3*2*1)
52 C 8 = (30,342,338,208,000)/(40,320)
52 C 8 = <font color=red>752,538,150</font>


Answer is <font color=red>752,538,150</font>
(approximately 752.5 million)
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