Question 1196829
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The length of a rectangle is 6 cm. greater than its width. If the width is 2 cm less and its
length is 3 cm. greater, the area would be the same as before. Find the dimensions of the
rectangle.
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x     = the width
(x+6) = the length.


Write equation as you read the problem

    x*(x+6) = (x-2)*((x+6)+3).


Simplify and find x

    x*(x+6) = (x-2)*(x+9)

    x^2 + 6x = x^2 - 2x + 9x - 18

    x^2 + 6x = x^2 + 7x - 18

          6x =       7x - 18

          18 =       7x - 6x

           x =         18


<U>ANSWER</U>.  The dimensions of the rectangle are 18 cm and 24 cm.
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Solved.