Question 1196813
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NOTE: The problem should not be posted this way; without any context, we have to assume that a and b are the minimum and maximum values of the random variable.  The problem only makes sense if that is the case -- but the problem should say so, instead of just saying a=10 and b=80.<br>
The allowable range for the variable is from 10 to 80, a range of 70; the prescribed range for this problem is from 52 to 80, a range of 28.  Since the distribution is uniform, the probability that x is greater than 52 is<br>
28/70 = 2/5 = 40%.<br>