Question 1196792
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If a formal algebraic solution is needed, use one like that provided in the response from the other tutor.<br>
But this kind of relatively easy problem can provide good problem-solving practice and good mental exercise by solving it using logical reasoning and basic arithmetic.<br>
(1) The required change is $9.50.
(2) If all 30 coins were quarters, that would be only $7.50, which is $2.00 short of the required total.
(3) Since each half dollar is worth $0.25 more than each quarter, the number of half dollars needed to make the addition $2.00 is 200/25 = 8.<br>
So there were 8 half dollars, which means 30-8 = 22 quarters.<br>
ANSWER: 8 half dollars; 22 quarters<br>
CHECK: 8(50)+22(25) = 400+550 = 950<br>