Question 1196707
log 2 (x-2) + log 2 (x+1) = 2
<pre>This appears to be base 2, and it seems as though you need this solved for x. If so, you need to communicate better!

It'd then be: {{{matrix(1,3, log (2, (x - 2)) + log (2, (x + 1)), "=", 2)}}}

If the above is true, then x = 3  or x = - 2, but - 2 is EXTRANEOUS, so the only solution would be: x = 3.

If the above is true, then {{{x <> 2sqrt(2)}}}, as the other person states!</pre>