Question 1196653
{{{4x+3y=6}}}

find the slope

{{{4x+3y=6}}}....solve for {{{y}}}

{{{3y=-4x+6}}}

{{{y=-(4/3)x+6/3}}}

{{{y=-(4/3)x+2}}}


=> the slope is {{{-(4/3)}}} and {{{y}}}-intercept is {{{2}}}

find the {{{x}}}-intercept

set {{{y=0}}}

{{{0=-(4/3)x+2}}}

{{{(4/3)x=2}}}

{{{x=2/(4/3)}}}...........simplify

{{{x=1/(2/3)}}}

{{{x=3/2}}}


{{{x}}}-intercept is {{{3/2}}}


{{{ drawing( 600, 600, -10, 10, -10, 10,
circle(3/2,0,.12),circle(0,2,.12),
locate(3/2,1.17,p(3/2,0)),locate(0.2,2,p(0,2)),
graph( 600, 600, -10, 10, -10, 10, -(4/3)x+2)) }}}