Question 1196620


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let games as they won be {{{x}}}
and games as they lost be {{{y}}}

total games played {{{162 }}}

 {{{x+y=162}}}.........eq.1

if team A won {{{36}}} less than {{{twice}}} as many games as they{{{ lost}}}, we have

{{{x=2y-36}}}............eq.2, substitute in eq.1

 {{{2y-36+y=162}}}........solve for {{{y}}}

{{{3y=162+36}}}

{{{3y=198}}}

{{{y=66}}}

go to

{{{x=2y-36}}}............eq.2, substitute {{{y}}}

{{{x=2*66-36}}}

{{{x=132-36}}}

{{{x=96}}}

  team A did have  {{{96}}} wins and  {{{66}}} losses