Question 1196610
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{{{log(225/36)-log(25/81)-log(64/729)}}}<br>
Use log(A)-log(B) = log(A/B):<br>
{{{log((225/36)(81/25)(729/64))}}}<br>
{{{log((225*81*729)/(36*25*64))}}}<br>
{{{log((9*9*729)/(4*64))}}}<br>
{{{log((3^10)/(2^8))}}}<br>
{{{10*log(3)-8*log(2)}}}<br>