<PRE><B>Question 113983</B>

{{{f(x)=5x^2-3x+1}}} Start with the given function.



{{{f(-2)=5(-2)^2-3(-2)+1}}} Plug in {{{x=-2}}}. In other words, replace each x with -2.



{{{f(-2)=5(4)-3(-2)+1}}} Evaluate {{{(-2)^2}}} to get 4.



{{{f(-2)=+20-3(-2)+1}}} Multiply 5 and 4 to get  20



{{{f(-2)=+20+6+1}}} Multiply -3 and -2 to get  6



{{{f(-2)=27}}} Now combine like terms</PRE>