Question 1196553
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The exp(−0.2t) can be written as e^(-0.2t) or {{{e^(-0.2t)}}}


As t approaches infinity, the exp(−0.2t) will approach 0


We can see this if we made a table of values
<table border = "1" cellpadding = "5"><tr><td>t</td><td>Exp(-0.2t)</td></tr><tr><td>10</td><td>0.1353</td></tr><tr><td>20</td><td>0.0183</td></tr><tr><td>30</td><td>0.0025</td></tr><tr><td>40</td><td>0.0003</td></tr></table>
As t gets bigger, exp(−0.2t) gets closer to 0.


Or we could look at the graph of y = e^(-0.2x) to see the curve slowly approaching the x axis. It never actually arrives at the x axis.
{{{drawing( 300, 300, -5, 5, -5, 5, 
         grid(1),
         graph(300,300,-5,5,-5,5,0,e^(-0.2x))
) }}}
You can use graphing tools like Desmos, GeoGebra, or a TI83 (or similar) to graph. 


Since the expression exp(-0.2t) approaches zero, it basically goes away when t approaches infinity.


So the v(t) approaches 54(1-0) = 54


Answer: Terminal velocity is 54 m/s
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