Question 1196532
<font color=black size=3>
If we are 92% confident, and generated 200 confidence intervals, then we should expect about 0.92*200 = 184 confidence intervals to contain the population parameter in question.


The remaining 200-184 = 16 intervals are expected to not have the population parameter.


Alternative calculation: (1-0.92)*200 = 16
Or 0.08*200 = 16


Answer: <font color=red>16</font>
</font>