Question 1196517
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There are 5 choices for the ball from the first bag and 6 choices for the ball from the second bag.  So the number of possible draws is 5*6 = 30; that is the denominator of all the probability fractions.<br>
(a) one ball is numbered 1, the other 6.  The 6 had to come from the second bag, so the 1 had to come from the first.
Number of favorable outcomes: 1*1 = 1; probability 1/30<br>
(b) both balls have an odd number.  3 possibilities from each bag.
Number of favorable outcomes: 3*3 = 9; probability 9/30<br>
(c) both balls have the same number.  That number can be 1, 2, 3, 4, or 5.
Number of favorable outcomes: 5; probability 5/30<br>
(d) the sum of the numbers on the ball is 9.  The combination can be 3+6, 4+5, or 5+4.
Number of favorable outcomes: 3; probability 3/30<br>
ANSWERS:
(a) 1/30
(b) 9/30 = 3/10
(c) 5/30 = 1/6
(d) 3/30 = 1/10<br>