Question 1196515
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Hi  

Group of 15:  12 girls, 3 boys
One child was chosen at random from the group. 
Another child was chosen at random from the remaining children.
Calculate the probability(express as fraction in simplest form):

(a) the first child chosen was a girl.  {{{12/15 = green(4/5)}}}
(b) the first chosen was a girl AND the second was a boy.  {{{(12/15)(3/14) = green(6/35)}}}
(c) a child of each sex was chosen. (b) OR  boy first & girl second
{{{green(6/35)}}}  + {{{(3/15)(12/14)}}} = {{{6/35 + 6/35 = green(12/35)}}}
Wish You the Best in your Studies.
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