Question 1196504
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A bit of commentary on @MathLover1's answer.


It's correct, but I would leave out the {{{m^3}}} part
The {{{m}}} refers to meters, and it is NOT a variable.
The {{{m^3}}} refers to cubic meters. Think of a 1 m by 1 m by 1 m cube.


I would write it as {{{10 = 2x^2y}}} which solves to {{{y = (5)/(x^2)}}}
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