Question 1196500
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<pre>

Let x be the slow speed (in heavy traffic), in kilometers per hour.

Then the faster speed was (2x-10) kilometers per hour, according to the problem.


Now write the total distance equation

    0.5x + 5*(2x-10) = 500.    (Here 0.5 represents 0.5 hour = 30 minutes).


Simplify and find x

    0.5x + 10x - 50 = 500

       10.5x         = 500 + 50 = 550

          x                    = 550/10.5 = 52.381 km/h.

<U>ANSWER</U>.  The average speed in slow traffic was 52.381 km/h.
</pre>

Solved.


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For simple Travel & Distance problems, &nbsp;see introductory lessons 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems.lesson>Travel and Distance problems</A>  

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems-for-two-bodies-moving-toward-each-other.lesson>Travel and Distance problems for two bodies moving in opposite directions</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Typical-catching-up-Travel-and-Distance-problems.lesson>Travel and Distance problems for two bodies moving in the same direction (catching up)</A>

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