Question 1196472
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Log Rules:
log(A)+log(B) = log(A*B)
log(A)-log(B) = log(A/B)
B*log(A) = log(A^B)


Use those rules to get:
log(x) + 2log(y) = 1
log(x) + log(y^2) = 1 
log(xy^2) = 1


Assuming base 10 logs, then,
log(xy^2) = 1
xy^2 = 10^1 
xy^2 = 10
y^2 = 10/x


Now let's use the second equation
x - 3y^2 = 13 
x - 3(10/x) = 13 
x - 30/x = 13 
x^2 - 30 = 13x
x^2-13x-30 = 0


In the second to last step, I multiplied both sides by x to clear out the fraction.
This is the same as multiplying every term by x. 
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