Question 1196459

{{{x+2y=-2}}}.......eq.1
{{{y=-2x-13}}}......eq.2
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start with 

{{{x+2y=-2}}}.......eq.1........solve for {{{x}}}

{{{x=-2y-2}}}.......eq.1a

go to

{{{y=-2x-13}}}......eq.2, substitute {{{x}}} from eq.1a


{{{y=-2(-2y-2)-13}}}.......... solve for {{{y}}}

{{{y=4y+4-13}}}

{{{y=4y-9}}}

{{{9=4y-y}}}

{{{9=3y}}}

{{{y=3}}}

go to eq.1a, substitute {{{3}}} for {{{y}}}



{{{x=-2*3-2}}}.......eq.1a

{{{x=-6-2}}}

{{{x=-8}}}


solution: {{{x=-8}}}, {{{y=3}}}