Question 1196453
let a = the number of kilograms eaten by each adult on the average.
let b = the number of kilograms eaten by each child on the average.
you get two equations.
they are:
28a + 37c = 12.67 kilograms
14a + 30c = 11.3 kilograms.
solve these two equations simultaneously to get:
c = .43173901304
a = -.1180124224
confirm these values are correct by replacing a and c in both original equations to get:
28 * -.1180124224 + 37 * .43173901304 = 12.67
14 * -.1180124224 + 30 * .43173901304 = 11.3
this confirms the values are correct.
unfortunately, the value of a is less than 0 which means that you don't have a solution to this system of equations where the average number of kilograms consumed by adults and children is positive for both.
since that is a requirement, then the system of equations does not have a common solution.
i also solved graphically where the intersection of the lines graphed by the two equations is at the intersection of those lines.
it confirms the common solution requires a negative value for the average number of kilograms consumed by the adults.
since this can't be, the solution is invalid.
here's the graph.
<img src = "http://theo.x10hosting.com/2022/091704.jpg">
however, you were not asked to solve the system of equations.
you were only asked to write two equations that could be used to solve the system.
your solution is the two equations shown above.
they are reproduced below for your convenience.
28a + 37c = 12.67 kilograms
14a + 30c = 11.3 kilograms.
a is the average number of kilograms of chips consumed by each adult.
c is the average number of kilograms of chips consumed by each child.