Question 1196421
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Here is an alternative to the standard method for solving the problem shown by the other tutor.<br>
The three times are 5, 8, and 10 hours.  Consider the least common multiple of those times, which is 40 hours.<br>
In 40 hours...
Pump A could empty the pool 40/5 = 8 times;
Pump B could empty it 40/8 = 5 times;
Pump C could empty it in 40/10 = 4 times<br>
So in 40 hours, the three pumps together could empty the pool 8+5+4 = 17 times.<br>
Therefore, the number of hours it would take the three pumps to empty the pool one time is 40/17.<br>
ANSWER: 40/17 hours<br>