Question 1196419
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<pre>

The line perpendicular to 3x+y = 1 is

    x - 3y = c,      (1)  where c is an arbitrary constant.


To specify the perpendicular line through the point (-2,1), put in equation (1)
x= -2,  y= 1.  You will get then

    c = -2 -3*1 = -2 - 3 = -5.


Thus the equation you are seeking for is  x - 3y = -5.    <U>ANSWER</U>
</pre>

Solved.


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For more details and other forms of reasoning, &nbsp;see the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/geometry/Equation-for--a-straight-line-perpendicular-to-a-given-line-and-passing-through-a-given-point.lesson>Equation for a straight line perpendicular to a given line and passing through a given point</A> 

in this site.