Question 113946

{{{(-18/6)x-42>0}}} Start with the given inequality




{{{(6)((-18/6)x-42)=(6)(0)}}} Multiply both sides by the LCM of 6. This will eliminate the fractions  (note: if you need help with finding the LCM, check out this <a href=http://www.algebra.com/algebra/homework/divisibility/least-common-multiple.solver>solver</a>)




{{{-18x-252=0}}} Distribute and multiply the LCM to each side




{{{-18x>0+252}}}Add 252 to both sides



{{{-18x>252}}} Combine like terms on the right side



{{{x<(252)/(-18)}}} Divide both sides by -18 to isolate x  (note: Remember, dividing both sides by a negative number flips the inequality sign) 




{{{x<-14}}} Divide


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Answer:

So our answer is {{{x<-14}}} 



which in interval notation looks like


*[Tex \LARGE \left(-\infty,-14\right\)]