Question 1196269

given:

{{{g(x)= f(x-2)}}} 

and {{{f(x)= 4-x^2}}}


find; the value of{{{g(0)}}}


first find  {{{g(x)}}} 

{{{g(x)= f(x-2)}}} 

{{{g(x)= 4-(x-2)^2}}} 

{{{g(x)= 4-(x^2 - 4x + 4)}}} 

{{{g(x)= 4-x^2 + 4x - 4}}} 

{{{g(x)= -x^2 + 4x }}} 


now find    {{{g(0)}}}


{{{g(0)= -0^2 + 4*0 }}} 

{{{g(0)= 0 }}}