Question 1196229
Lotteries The Sad State Lottery requires you to select a sequence of four different numbers 
from 0 through 68. (Order is important.) 
You are a Winner if your sequence agrees with that in the drawing, 
and you are a Booby Prize Winner if your selection of numbers is correct, but in the wrong order. 
(a) What is the probability of being a Winner? (Enter your probabilities as fractions.)
(b) What is the probability of being a Booby Prize Winner?
(c) What is the probability that you are either a Winner or a Booby Prize Winner?
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(a)  In all, there are 69 numbers, from which the organizers of the lottery select 4 numbers.


     There are 69*68*67*66 = 20748024 different ORDERED sequences of 4 numbers from 69 numbers,
     that you may have on your ticket, so the number of tickets in the lottery is 20748024,
     and only one of them is a Winner.

     Therefore, the probability to be a Winner, having one ticket, is  P = {{{1/20748024}}}.    <U>ANSWER to (a)</U>



(b)  The number of "happy" tickets for to be a Booby Prize Winner is  4! -1 = 1*2*3*4 - 1 = 24 - 1 = 23
        (permutations of 4 happy numbers minus one Winner ticket)


    Therefore, the probability to be a Booby Prize Winner, having one ticket, is  

        P = {{{23/20748024}}} = {{{1/902088}}}.    <U>ANSWER to (b)</U>



(c)  The probability to be either-or in this case is  {{{24/20748024}}} = {{{1/864501}}}.   <U>ANSWER to (c)</A>
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Solved.