Question 1196215
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Two factory plants are making TV panels. Yesterday, Plant A produced  3000 panels. 
Ten percent of the panels from Plant A and  3%of the panels from Plant B were defective. 
How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was 6% ?
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Let x = How many panels did Plant B produce.

The number of defective panels from plant A is 0.1*3000.

The number of defective panels from plant B is 0.03*x


The total defective panels from both plants is

    0.1*3000 + 0.03x = 0.06*(3000+x).


Simplify and find x

    300 + 0.03x = 180 + 0.06x

    300 - 180 = 0.06x - 0.03x

       120    =     0.03x

        x     =     120/0.03 = 4000.


<U>ANSWER</U>.  Plant B produced 4000 panels.
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Solved.