Question 1196211

I will answer it as stated.

three consecutive even integers are {{{2n}}}, {{{2n + 2}}},{{{ 2n + 4}}}
 
 if twice the first integer added to the second is {{{268214}}},  we have


{{{(2n)*2 + (2n + 2) = 268262}}}

{{{6n + 2 = 268262}}}

{{{6n = 268260}}}

{{{n = 44710}}}
 
Then the three consecutive even integers are  {{{8942}}},{{{ 9422}}},{{{ 89424}}}