Question 1196173
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Here is a quick and easy non-algebraic method for solving any 2-part "mixture" problem like this.<br>
(1) $1000 interest on a $10,000 investment is a return of 10%
(2) 10% is 3/4 of the way from 4% to 12% (use a number line to see that, if it helps)
(3) Therefore, 3/4 of the total needs to be invested at the higher rate<br>
ANSWER: 3/4 of $10,000, or $7500, should be invested at 12%; the other $2500 at 4%<br>
CHECK: .12($7500)+.04($2500)=$900+$100 = $1000<br>