Question 113898
The general equation of a circle is {{{(x-h)^2+(y-k)^2=r^2}}} where (h,k) is the center and r is the radius.


So using this equation, we get


{{{(x-3)^2+(y-(-2))^2=4^2}}} Plug in h=3,k=-2, and r=4. These are given



{{{(x-3)^2+(y+2)^2=4^2}}} Rewrite {{{y-(-2)}}} as {{{y+2}}}


{{{(x-3)^2+(y+2)^2=16}}} Square 4 to get 16



So the equation for the circle with center C(3,-2) and radius 4 is {{{(x-3)^2+(y+2)^2=16}}}