Question 1196055
{{{f(x)=2x^2+x-3}}}

{{{g(x)=x+2}}}

then

{{{f(x)/g(x)=(2x^2+x-3)/(x+2)}}}...........use long division


...........({{{2x-3}}}
{{{(x+2)}}}|{{{2x^2+x-3}}}
............{{{2x^2+4x}}}.....subtract

................{{{-3x}}}....bring down {{{-3}}}


...............{{{-3x-3}}} 
...............{{{-3x-6}}} ....subtract
.......................{{{3}}}.......reminder

 
so,

{{{f(x)/g(x)= 2x -3+ 3/(x + 2) }}}