Question 1196000
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a rectangle is expending in area its width is x cm is length is always 4times its width find the area of retangle with respect to its width x, when the area of triangle is 225
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Change the exercise to this:
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A rectangle is expending in area. Its width is x cm.  Its length is always 4 times its width. Find the area of rectangle with respect to its width x, when the area of rectangle is 225 square cms.
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Something seems wrong with the question part.  Is that a question of RATIO of area to width?


{{{x}}}, width
{{{4x}}}, length
{{{4x^2}}}, area


{{{4x^2=225}}}

{{{2x=sqrt(225)}}}

{{{2x=sqrt(5*5*3*3)}}}

{{{highlight_green(x=15/2)}}}


If "area with respect to width" means  AREA : WIDTH or {{{AREA/WIDTH}}}, then this is
{{{225/(15/2)}}}

{{{225*(2/15)}}}

{{{highlight(30)}}}.