Question 1195987
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The problem asks for the distance from kimani's house when the two meet, so what we need to determine is the distance kimani travels before they meet.<br>
He leaves 1.5 hours before mwaura; traveling 15km/h, he travels 1.5(15) = 22.5km before mwaura starts; that leaves 40-22.5 = 17.5km.<br>
When they are both riding, the ratio of their speeds is 15:25 = 3:5.  That means kimani rides 3/8 of the remaining 17.5km before they meet.<br>
(3/8)(17.5) = (3/8)(35/2) = 105/16 = 6.5625 km<br>
So the total distance kimani rides before they meet is<br>
22.5 + 6.5625 = 29.0625km<br>
ANSWER: 29.0625km<br>