Question 1195987
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Noting that Kimani will travel (15km/hr)*(1.5hrs) = 22.5km  before Mwaura starts, we can write the following, setting t = 0  to be noon:

1.  Dk_k(t) = 15t + 22.5
2.  Dk_m(t) = 40 - 25t 

Where each Dk(t) is distance from Kimani's house.

When the two meet, their distances from Kimani's will be equal, so set eq 1 equal to eq 2.   Then solve for t to get <b>t = 0.4375hr</b>

At t=0.4375hr,   Dk_k(t) = 15(0.4375) + 22.5 = 6.5625 + 22.5 = 29.0625km

Check using Dk_m(t):
    at t=0.4375hr,  Dk_m(t) = 40 - 25(0.4375) = 29.0625km