Question 1195942
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The distances going and returning are the same; and the return trip is at a speed twice the speed of the trip to school.<br>
That means the amount of time for the return trip is half the time for the trip there.<br>
Then, since the total time was 1 hour 30 minutes, he spent 1 hour at 22mph going and a half hour at 44mph returning.<br>
Use either time and speed (rate) to find that the distance (rate times time) is 22 miles.<br>