<PRE><B>Question 1195909</B>
&lt;br&gt;
The other tutor showed a typical formal algebraic solution, using a standard method for setting up the problem.  Here is a very different approach.&lt;br&gt;
The difference in their ages is now, and will always be, 6 years.&lt;br&gt;
When Nelson is 20% older than Meg, that &quot;20% older&quot; will be &quot;6 years older&quot;.&lt;br&gt;
So if x is Meg&#39;s age when Nelson is 20% older, then&lt;br&gt;
.20(x) = 6
x = 6/.20 = 30&lt;br&gt;
So when Meg is 30, Nelson will be 36.  (6 years older than 30 is 36; and 20% older than 30 is 30+6=36.)&lt;br&gt;
That will happen 16 years from now, so their ages now are 14 and 20.&lt;br&gt;
And so 10 years from now their ages will be 24 and 30.&lt;br&gt;
ANSWERS: Meg 24, Nelson 30.&lt;br&gt;

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