<PRE><B>Question 1195917</B>
Determine whether the relation is a function.


 t​{(4​,8​),(20,-9),(36​,8​),(4​,6​),(50​,​6)}

to determine whether the relation is a function, we look at the inputs and outputs;

A relation is a function if the {{{x}}}-values map to only one {{{y}}}-value. In other words, if a relation is one-to-one or many-to-one it is a function.

One-to-one: Each {{{x}}}-value corresponds to one distinct {{{y}}}-value
Many-to-many: Multiple {{{x}}}-values correspond to multiple {{{y}}}-values.

in your case 

x-values are: {{{4}}},{{{20}}},{{{36}}},{{{4}}},{{{50}}}
 y-values are: {{{8}}},{{{-9}}},{{{8}}},{{{6}}},{{{6}}}

Since x=4produces y=8 and y=6, the relation  t​{(4​,8​),(20,-9),(36​,8​),(4​,6​),(50​,​6)} is {{{not}}} a function.



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