Question 1195916
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{{{(10^x+10^(-x))/(10^x-10^(-x))}}}

= {{{(10^x+10^(-x))*(10^x+10^(-x))/((10^x-10^(-x))*(10^x+10^(-x)))}}}

= {{{(10^x+10^(-x))^2/(10^2x - 10^(-2x))}}}

= {{{(10^(2x) - 10^(-2x) + 2)/(10^(2x) - 10^(-2x))}}}

= {{{1 + 2/(10^(2x) - 10^(-2x))}}}

{{{x<>0}}}