Question 113832
find the quadratic relation in vertex form that has zeros -3 and 5 and passes through (3,6). 
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f(x) = a(x+3)(x-5)
f(3)=6
Therefore:
f(3) = a(3+3)(3-5)=6
a*6*-2=6
-12a = 6
a = -1/2
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EQUATION:
f(x) = (-1/2)(x+3)(x-5)
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This quadratic has zeros at x=-3,and x=5, and passes thru (3,6)
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Cheers,
Stan H.