Question 1195355
Let's determine our numbers first

n = first number
2n+8 = 8 more than twice the number
62 = sum of the two numbers

Put the equation together: n+2n+8=62

Combine like terms: 3n+8=62

Subtract 8 from both sides: 3n=54

Divide 3 by both sides: n=18

Plug 18 into the original equation: 18+2(18)+8=62

Solve using order of operations: 18+36+8=62
54+8=62
62=62