Question 1195775
This is binomial because n is fixed, assume constant probability and independence of random samples.
a. 8C3*0.3^3*0.7^5=0.2541
b. look at 0,1,2
for 0 it is 0.7^8=0.0576
for 1 it I 8*0.3*0.7^7=0.1977
for 2 it is 28*0.3^2*0.7^6=0.2965
The sum of those is 0.5088
so at least 3 is everything else or 1-0.5088 or 0.4912 .
c. More than 3 is 0.4912-0.2541, which is exactly 3=0.2371