Question 1195729
Not a fixed number of attempts, so use Poisson.
e^(-0.44)*0.44^1/1!=0.2834 or 0.283 for 1 hurricane
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for 0 hurricanes it is e^(-0.44)=0.6440 or 0.644
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For both 0 and 1, the probability is the sum or 0.923.
That is the probability that at most 1 hurricane.
the probability of more than 1 hurricane is the complement off that or 0.077.