Question 1195726
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There are 3*3*3 = 27 possible outcomes

# correct   Formulation              Probability      Notes
   0        (2/3)*(2/3)*(2/3)            8/27       
   1        3C1*(1/3)*(2/3)*(2/3)       12/27         3C1 = 3!/(2!*1!) = 3
   2        3C2*(1/3)*(1/3)*(2/3)        6/27         3C2 = 3!/(1!*2!) = 3 
   3        (1/3)*(1/3)*(1/3)            1/27