Question 1195409
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I'm assuming you meant to say *[tex \large \text{f}(\text{x}) = \log_{3}(\text{x})] where the '3' is a subscript.


If so, then the inverse is *[tex \large \text{f}^{-1}(\text{x}) = 3^{\text{x}}] because exponential functions undo logarithmic ones, and vice versa. 


Note that 3 is the base of the log and it's also the base of the exponential.


In general, the inverse of *[tex \large \text{f}(\text{x}) = \log_{b}(\text{x})] is *[tex \large \text{f}^{-1}(\text{x}) = b^{\text{x}}] where b > 0 and {{{b <> 1}}}


Graph:
<img width="50%" src = "https://i.imgur.com/AJDO04a.png">
Notes:<ul><li>One curve is a reflection of the other. The mirror line is y = x</li><li>The domain and range swap roles between the original and the inverse function.</li></ul>
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