<PRE><B>Question 1195376</B>
&lt;pre&gt;
For the line  Ax + By = C,  the slope is  -A/B  (and y-intercept is C/B).

A = 2/3
B = 5/7
C = 1

The slope of the given line is thus   -(2/3)/(5/7) = -(2/3)*(7/5) = -14/15


The slope of line perpendicular to a given line, is found as follows:
         (slope of perpendicular line)  =  -1/(slope of given line) 

Thus, if we write the equation of the perpendicular line as y = mx + b,
then   m = -1 / (-14/15) = 15/14.

You can then write:   y = (15/14)x + b      (*)

Since the problem does not give a point of intersection of the two lines, there is no specific solution.  The x-intercept and y-intercept depend on WHERE the two lines meet.   We can only write the FORM of the y-intercept and x-intercept:

     y-intercept (set x=0):  y = b
     x-intercept (set y=0, solve for x):  x = -(14/15)b

If you know the point where the lines intersect, then you can solve (*) for b, and then plug that value of b into the bottom two equations to get specific (numerical) intercepts.
</PRE>