Question 1195341
Given line equation {{{2x-3y=6}}}
{{{-3y=-2x+6}}}

{{{y=(2/3)x-2}}}

and the intercepts on axes,
(0,-2) and  (3,0).


You want the line with slope {{{-3/2}}}, and containing the point having the coordinates point (3/2,-1).

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