Question 1195248
<pre>
{{{drawing(14080/69,400,-10,166,-65,280,

line(0,0,156,0),line(0,0,132.9230769,-55.38461539), line(156,0,132.9230769,-55.38461539),
line(0,0,156,270.199926), line(156,0,156,270.199926),
locate(-10,7,A), locate(160,7,C), locate(160,277.2,B),
locate(130,-54,D), green(line(0,0,0,140)), locate(3,55,30^o),
locate(115,-27,90^o),
locate(145,-24,60), locate(46,-27,144)



)}}}
In right triangle ACD, use the Pythagorean theorem to 
find the hypotenuse AC.

Since the bearing angle from A is 30<sup>o</sup>, angle BAC is 
its complement, or 60<sup>o</sup>.

Since ABC is a 30-60-90 right triangle, we can
use the fact that the sides are in the ratio 1:√3:2,
to set up the proportional equation:

{{{AC/1}}}{{{""=""}}}{{{BC/sqrt(3)}}}

Solve for BC.

Edwin</pre>