Question 1195258
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(a) {{{sin^(-1) (-1)}}} = {{{- pi/2}}}     ( since  {{{sin(- pi/2)}}} = {{{-1}}} ).


(b) {{{tan^(-1) (-1)}}} = {{{- pi/4}}}     ( since  {{{tan(- pi/4)}}} = {{{-1}}} ).
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Solved.



In this post, &nbsp;I treat &nbsp;{{{sin^(-1) (x)}}}  &nbsp;as  &nbsp;arcsin(x)  &nbsp;and treat &nbsp;{{{tan^(-1) (x)}}} &nbsp;as &nbsp;arctan(x).