Question 1195191
<br>
{{{(tan(theta)-3)(25sin^2(theta)-1)=0}}}<br>
The second factor can be factored as a difference of squares:<br>
{{{(tan(theta)-3)(5sin(theta)+1)(5sin(theta)-1)=0}}}<br>
Then<br>
{{{tan(theta)=3}}} or {{{sin(theta)=-1/5}}} or {{{sin(theta)=1/5}}}<br>
Use a calculator if you need to get the answers in terms of angles.<br>