Question 1195175
.
Hi
The sum of Sofia and her mothers age is twice the difference between their ages. 
5 years ago Sofia's mother is 4 times as old as Sofia. How old are they now.

Thank you 
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            As  {{{highlight(usual)}}},  the solution and the answer from the post of @josgarithmetic 

            (5  years for daughter and  15  years for her mother)  are both  {{{highlight(WRONG)}}}  and  {{{highlight(INCORRECT)}}}.


            I came to bring you a correct solution.



<pre>
d,m;
{{{system(d+m=2(m-d),m-5=4(d-5))}}}


-
d+m = 2m-2d
2m-2d = d+m
m-3d = 0
m=3d
-
m-5=4d-20
m=4d-15
-
3d = 4d-15
0 = d-15
0 = d-15
d = 15
-
Sofia is 15 years old;  her mother is 45 years old.    <U>ANSWER</U>


You may check it on your own that all conditions of the problem are satisfied.
</pre>

Solved.


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For the safety of your brain, &nbsp;ignore the post by @josgarithmetic.