Question 1195067
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2 solutions....<br>
(1) One with positive leading coefficient, the other with negative
Example: y=x^2-1 and y=-x^2+1
graph:<br>
{{{graph(200,200,-3,3,-3,3,x^2-1,-x^2+1)}}}<br>
(2) Same thing, but with different axes of symmetry
Example: y=x^2-1 and y=-x^2+2x
graph:<br>
{{{graph(200,200,-3,3,-3,3,x^2-1,-x^2+2x)}}}<br>
(3) Two with different positive leading coefficients; vertices one above the other
Example: y=x^2 and y=(1/2)x^2+1
graph:<br>
{{{graph(200,200,-3,3,-1,5,x^2,(1/2)x^2+1)}}}<br>
or 1 solution....<br>
(1) same vertex but opening different directions (single intersection at the common vertex)
Example: y=x^2 and y=-x^2
graph:
{{{graph(200,200,-3,3,-3,3,x^2,-x^2)}}}<br>
(2) single intersection not at either vertex
Example: y=x^2+2x and y=-x^2+2x
graph:
{{{graph(200,200,-3,3,-3,3,x^2+2x,-x^2+2x)}}}<br>