Question 1195043
Two sides of a triangle field measure 325 meters and 278 meters. If these sides form an angle of 47°40’, what is the length of the fence that will surround the field?
<pre>Using law of cosines, we get: {{{matrix(4,3, a^2, "=", b^2 + c^2 - 2(bc) * cos (A), a^2, "=", 325^2 + 278^2 - 2(325)(278) * cos (47 + 40/60)^o, a, "=", sqrt(325^2 + 278^2 - 2(325)(278) * cos (47&2/3)^o), a, "=", "247.42_(rounded)")}}}
You now have the 3 sides (a, b, and c) of the triangle. I take it you know how to calculate the perimeter of this triangle, correct?